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SCERT KeralaClass 10 ยท Chemistry

Periodic Table & Subshell Electronic Configuration

TEACHER ANSWER KEY & DERIVATIONS
Q1.

What is the maximum number of electrons that can be accommodated in the d-subshell?

[1 Mark]
(A)

2

(B)

6

(C)

10

โœ“ Correct
(D)

14

Step-by-Step Solution & KaTeX Derivation:

Subshells hold maximum electrons: s = 2, p = 6, d = 10, f = 14.

Q2.

Which block in the periodic table contains elements with valence electrons entering the s-subshell?

[1 Mark]
(A)

s-block

โœ“ Correct
(B)

p-block

(C)

d-block

(D)

f-block

Step-by-Step Solution & KaTeX Derivation:

Groups 1 and 2 belong to the s-block as their outermost electrons enter the s-subshell.

Q3.

What is the subshell electronic configuration of Sodium (Na, Atomic Number 11)?

[1 Mark]
(A)

1s^2 2s^2 2p^6 3s^1

โœ“ Correct
(B)

1s^2 2s^2 2p^5 3s^2

(C)

1s^2 2s^2 2p^7

(D)

1s^2 2s^4 2p^5

Step-by-Step Solution & KaTeX Derivation:

Sodium (Z = 11) subshell electronic configuration: 1s^2 2s^2 2p^6 3s^1.

Q4.

How is the period number of an element determined from its subshell configuration?

[1 Mark]
(A)

Number of valence electrons

(B)

Highest principal quantum number (shell number)

โœ“ Correct
(C)

Total number of subshells

(D)

Atomic mass

Step-by-Step Solution & KaTeX Derivation:

The highest shell number in configuration indicates the period of the element.

Q5.

What is the group number of an element with outer configuration 3s^2 3p^4?

[1 Mark]
(A)

Group 4

(B)

Group 6

(C)

Group 14

(D)

Group 16

โœ“ Correct
Step-by-Step Solution & KaTeX Derivation:

For p-block elements: Group number = 12 + valence p-electrons = 12 + 4 = Group 16.

Q6.

Which block of elements generally exhibit variable oxidation states?

[1 Mark]
(A)

s-block

(B)

p-block

(C)

d-block

โœ“ Correct
(D)

Noble gases

Step-by-Step Solution & KaTeX Derivation:

Transition metals (d-block) exhibit variable oxidation states due to small energy difference between (n-1)d and ns subshells.

Q7.

What is the oxidation state of Fe in FeCl3?

[1 Mark]
(A)

+1

(B)

+2

(C)

+3

โœ“ Correct
(D)

-3

Step-by-Step Solution & KaTeX Derivation:

Chlorine has -1 oxidation state. Fe+3(โˆ’1)=0โ‡’Fe=+3\text{Fe} + 3(-1) = 0 \Rightarrow \text{Fe} = +3.

Q8.

Which subshell has lower energy and is filled before 3d?

[1 Mark]
(A)

3p

(B)

4s

โœ“ Correct
(C)

4p

(D)

3s

Step-by-Step Solution & KaTeX Derivation:

According to Aufbau principle, 4s (n+l=4+0=4n+l = 4+0=4) fills before 3d (n+l=3+2=5n+l = 3+2=5).

Q9.

Elements in Group 18 of the periodic table are known as:

[1 Mark]
(A)

Alkali Metals

(B)

Halogens

(C)

Noble / Inert Gases

โœ“ Correct
(D)

Lanthanides

Step-by-Step Solution & KaTeX Derivation:

Group 18 elements have complete octet configuration (ns^2 np^6) and are unreactive noble gases.

Q10.

What is the noble gas shorthand configuration for Chlorine (Cl, Atomic Number 17)?

[1 Mark]
(A)

[Ne] 3s^2 3p^5

โœ“ Correct
(B)

[Ar] 4s^1

(C)

[He] 2s^2 2p^6

(D)

[Ne] 3s^1 3p^6

Step-by-Step Solution & KaTeX Derivation:

Neon core is 10 electrons. 17โˆ’10=7โ‡’[Ne]ย 3s2ย 3p517 - 10 = 7 \Rightarrow [\text{Ne}]\ 3s^2\ 3p^5.

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